(x^2-7x+12)^x^2-3x+2=1

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Solution for (x^2-7x+12)^x^2-3x+2=1 equation: 



(x^2-7x+12)^x^2-3x+2=1

We move all terms to the left:

(x^2-7x+12)^x^2-3x+2-(1)=0

We add all the numbers together, and all the variables

-3x+(x^2-7x+12)^x^2+1=0

We move all terms containing x to the left, all other terms to the right

-3x+(x^2-7x+12)^x^2=-1

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